What is (x+2/3)^2+(y+2)^2=16 ?

The solution to (x+2/3)^2+(y+2)^2=16 is Circle with (a,b)=(-2/3 ,-2),r=4

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(x+2/3)^2+(y+2)^2=16

(x + \frac{2}{3})^{2} + (y + 2)^{2} = 16

(a, b) = (- \frac{2}{3}, - 2), r = 4

Solution steps

(x + \frac{2}{3})^{2} + (y + 2)^{2} = 16

Rewrite

(x + \frac{2}{3})^{2} + (y + 2)^{2} = 16

in the form of the standard circle equation

(x - (- \frac{2}{3}))^{2} + (y - (- 2))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- \frac{2}{3}, - 2), r = 4

What is (x+2/3)^2+(y+2)^2=16 ?
The solution to (x+2/3)^2+(y+2)^2=16 is Circle with (a,b)=(-2/3 ,-2),r=4