What is y^2=8x-2-13-x^2 ?

The solution to y^2=8x-2-13-x^2 is Circle with (a,b)=(4,0),r=1

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y^2=8x-2-13-x^2

y^{2} = 8 x - 2 - 13 - x^{2}

(a, b) = (4, 0), r = 1

Solution steps

y^{2} = 8 x - 2 - 13 - x^{2}

Rewrite

y^{2} = 8 x - 2 - 13 - x^{2}

in the form of the standard circle equation

(x - 4)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (4, 0), r = 1

4 x^{2} + 4 y^{2} - 24 x + 16 y + 51 = 0

3^{2} = (x - 2)^{2} + [y - (- 3)]^{2}

x^{2} + y^{2} - x + 3 y - \frac{3}{2} = 0

(x + 5)^{2} + (y - 2)^{2} = 11

(x - 2)^{2} + (y + 4)^{2} = 13.19 9^{2}

What is y^2=8x-2-13-x^2 ?
The solution to y^2=8x-2-13-x^2 is Circle with (a,b)=(4,0),r=1