What is x^{(2)}+y^{(2)}-2x+4y-11=0 ?

The solution to x^{(2)}+y^{(2)}-2x+4y-11=0 is Circle with (a,b)=(1,-2),r=4

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x^{(2)}+y^{(2)}-2x+4y-11=0

x^{(2)} + y^{(2)} - 2 x + 4 y - 11 = 0

(a, b) = (1, - 2), r = 4

Solution steps

x^{2} + y^{2} - 2 x + 4 y - 11 = 0

Rewrite

x^{2} + y^{2} - 2 x + 4 y - 11 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 2))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, - 2), r = 4

x^{2} + y^{2} + 4 x - 10 y + 28 = 0

x^{2} + y^{2} - 18 x + 8 y + 48 = 0

2 x^{2} + 2 y^{2} = 1

2 x^{2} + 2 y^{2} = 4

x^{2} + y^{2} - 12 x - 10 y = 12

What is x^{(2)}+y^{(2)}-2x+4y-11=0 ?
The solution to x^{(2)}+y^{(2)}-2x+4y-11=0 is Circle with (a,b)=(1,-2),r=4