What is 8x^2+8y^2-20+64y-371=0 ?

The solution to 8x^2+8y^2-20+64y-371=0 is Circle with (a,b)=(0,-4),r=(sqrt(519))/(2sqrt(2))

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8x^2+8y^2-20+64y-371=0

8 x^{2} + 8 y^{2} - 20 + 64 y - 371 = 0

(a, b) = (0, - 4), r = \frac{519}{2 2}

Solution steps

8 x^{2} + 8 y^{2} - 20 + 64 y - 371 = 0

Rewrite

8 x^{2} + 8 y^{2} - 20 + 64 y - 371 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 4))^{2} = (\frac{519}{2 2})^{2}

Therefore the circle properties are:

(a, b) = (0, - 4), r = \frac{519}{2 2}

(a + bi) (a - bi) = 25

x^{2} + y^{2} + 2 x - 2 y = 2

x^{2} + y^{2} + 2 x - 2 y = 3

3 x^{2} - 2 x + 3 y^{2} + y - 6 = 0

x^{2} + y^{2} + 8 x - 4 y - 2 = 0

What is 8x^2+8y^2-20+64y-371=0 ?
The solution to 8x^2+8y^2-20+64y-371=0 is Circle with (a,b)=(0,-4),r=(sqrt(519))/(2sqrt(2))