What is x^2+2x+y^2-6y+1=0 ?

The solution to x^2+2x+y^2-6y+1=0 is Circle with (a,b)=(-1,3),r=3

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x^2+2x+y^2-6y+1=0

x^{2} + 2 x + y^{2} - 6 y + 1 = 0

(a, b) = (- 1, 3), r = 3

Solution steps

x^{2} + 2 x + y^{2} - 6 y + 1 = 0

Rewrite

x^{2} + 2 x + y^{2} - 6 y + 1 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 3)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 1, 3), r = 3

What is x^2+2x+y^2-6y+1=0 ?
The solution to x^2+2x+y^2-6y+1=0 is Circle with (a,b)=(-1,3),r=3