What is (x+2)^2+(y+4)^2=9 ?

The solution to (x+2)^2+(y+4)^2=9 is Circle with (a,b)=(-2,-4),r=3

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(x+2)^2+(y+4)^2=9

(x + 2)^{2} + (y + 4)^{2} = 9

(a, b) = (- 2, - 4), r = 3

Solution steps

(x + 2)^{2} + (y + 4)^{2} = 9

Rewrite

(x + 2)^{2} + (y + 4)^{2} = 9

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 4))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 4), r = 3

(x - 1)^{(2)} + (y - 5)^{(2)} = 16

4 y^{2} + 4 x^{2} - 24 x + 32 y = - 84

x^{2} + y^{2} + 14 x - 7 y + 40 = 0

9 x^{2} + 36 x + 9 y^{2} + 72 y = - 155

(y + 4)^{2} + (x - 3)^{2} = 25

What is (x+2)^2+(y+4)^2=9 ?
The solution to (x+2)^2+(y+4)^2=9 is Circle with (a,b)=(-2,-4),r=3