What is 2x^2+6x+4y-8=0 ?

The solution to 2x^2+6x+4y-8=0 is Parabola with (h,k)=(-3/2 , 25/8),p=-1/2

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2x^2+6x+4y-8=0

2 x^{2} + 6 x + 4 y - 8 = 0

(h, k) = (- \frac{3}{2}, \frac{25}{8}), p = - \frac{1}{2}

Solution steps

2 x^{2} + 6 x + 4 y - 8 = 0

Rewrite

2 x^{2} + 6 x + 4 y - 8 = 0

in the standard form

4 (- \frac{1}{2}) (y - \frac{25}{8}) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, \frac{25}{8}), p = - \frac{1}{2}

y^{2} + 4 x - 14 y = - 53

x^{2} + y = 9

4 y^{2} + 9 y^{2} + 32 x - 18 y + 37 = 0

x^{2} - 6 x - 5 y - 1 = 0

x = y^{2} + 4 y - 6

What is 2x^2+6x+4y-8=0 ?
The solution to 2x^2+6x+4y-8=0 is Parabola with (h,k)=(-3/2 , 25/8),p=-1/2