What is 3x^2+3(y+1)^2= 1/3 ?

The solution to 3x^2+3(y+1)^2= 1/3 is Circle with (a,b)=(0,-1),r= 1/3

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3x^2+3(y+1)^2= 1/3

3 x^{2} + 3 (y + 1)^{2} = \frac{1}{3}

(a, b) = (0, - 1), r = \frac{1}{3}

Solution steps

3 x^{2} + 3 (y + 1)^{2} = \frac{1}{3}

Rewrite

3 x^{2} + 3 (y + 1)^{2} = \frac{1}{3}

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 1))^{2} = (\frac{1}{3})^{2}

Therefore the circle properties are:

(a, b) = (0, - 1), r = \frac{1}{3}

x^{2} + (y + 1)^{2} = 25

\frac{x ^{2} + y ^{2} - 2 x + y - 3}{2} \geq 0

x^{2} + (y + 1)^{2} = 16

(x - 1)^{2} + (y + 4)^{2} = 1

18 x^{2} + 18 y^{2} - 36 = 0

What is 3x^2+3(y+1)^2= 1/3 ?
The solution to 3x^2+3(y+1)^2= 1/3 is Circle with (a,b)=(0,-1),r= 1/3