What is (x-(-1))^2+(y-(-5))^2=10^2 ?

The solution to (x-(-1))^2+(y-(-5))^2=10^2 is Circle with (a,b)=(-1,-5),r=10

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(x-(-1))^2+(y-(-5))^2=10^2

(x - (- 1))^{2} + (y - (- 5))^{2} = 1 0^{2}

(a, b) = (- 1, - 5), r = 10

Solution steps

(x - (- 1))^{2} + (y - (- 5))^{2} = 1 0^{2}

Rewrite

(x - (- 1))^{2} + (y - (- 5))^{2} = 1 0^{2}

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 5))^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 5), r = 10

y^{2} = 4 x - x^{2}

x^{2} + y^{2} - 4 x - 18 y + 36 = 0

x^{2} + y^{2} - 45 = 0

x^{2} + y^{2} = 3469

(x - (- 2))^{2} + (y - (- 5))^{2} = 1 2^{2}

What is (x-(-1))^2+(y-(-5))^2=10^2 ?
The solution to (x-(-1))^2+(y-(-5))^2=10^2 is Circle with (a,b)=(-1,-5),r=10