What is (3X-2)^2+(3Y+6)^2=144 ?

The solution to (3X-2)^2+(3Y+6)^2=144 is Circle with (a,b)=(2/3 ,-2),r=4

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(3X-2)^2+(3Y+6)^2=144

(3 X - 2)^{2} + (3 Y + 6)^{2} = 144

(a, b) = (\frac{2}{3}, - 2), r = 4

Solution steps

(3 X - 2)^{2} + (3 Y + 6)^{2} = 144

Rewrite

(3 X - 2)^{2} + (3 Y + 6)^{2} = 144

in the form of the standard circle equation

(X - \frac{2}{3})^{2} + (Y - (- 2))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (\frac{2}{3}, - 2), r = 4

x^{2} + 5 x + y^{2} - y = \frac{5}{2}

(x - 1)^{2} + (y - 4)^{2} = 10

(x - 1)^{2} + (y - 4)^{2} = 17

(x - 5)^{2} + (y + 3)^{2} = 36

3 (x - 4)^{2} + 3 y^{2} = 3

What is (3X-2)^2+(3Y+6)^2=144 ?
The solution to (3X-2)^2+(3Y+6)^2=144 is Circle with (a,b)=(2/3 ,-2),r=4