What is 2(y+1)=(1/2 (x-1))^2 ?

The solution to 2(y+1)=(1/2 (x-1))^2 is Parabola with (h,k)=(1,0),p=2

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2(y+1)=(1/2 (x-1))^2

2 (y + 1) = (\frac{1}{2} (x - 1))^{2}

(h, k) = (1, 0), p = 2

Solution steps

2 (y + 1) = (\frac{1}{2} (x - 1))^{2}

Rewrite

2 (y + 1) = (\frac{1}{2} (x - 1))^{2}

in the standard form

4 \cdot 2 (y - 0) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 0), p = 2

(x - 2)^{2} = 8 (y + 1)

9 x^{2} - 12 x - 36 y - 32 = 0

y^{2} + 4 x - y + 5 = 0

y^{2} = 16 x - 8

y^{2} = 5 x + 3

What is 2(y+1)=(1/2 (x-1))^2 ?
The solution to 2(y+1)=(1/2 (x-1))^2 is Parabola with (h,k)=(1,0),p=2