What is x^2+y^2-14y+34=50 ?

The solution to x^2+y^2-14y+34=50 is Circle with (a,b)=(0,7),r=sqrt(65)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-14y+34=50

x^{2} + y^{2} - 14 y + 34 = 50

(a, b) = (0, 7), r = 65

Solution steps

x^{2} + y^{2} - 14 y + 34 = 50

Rewrite

x^{2} + y^{2} - 14 y + 34 = 50

in the form of the standard circle equation

(x - 0)^{2} + (y - 7)^{2} = (65)^{2}

Therefore the circle properties are:

(a, b) = (0, 7), r = 65

x^{2} + y^{2} - 8 y + 4 x + 9 = 0

x^{2} + y^{2} + 6 y - 72 = 0

x^{2} - 5 x + y^{2} = 0

x^{2} + y^{2} - y - 1 = 0

2 x^{2} + 2 y^{2} = 32

What is x^2+y^2-14y+34=50 ?
The solution to x^2+y^2-14y+34=50 is Circle with (a,b)=(0,7),r=sqrt(65)