x^2+4x-8y+4=0

Lösung

x^{2} + 4 x - 8 y + 4 = 0

(h, k) = (- 2, 0), p = 2

Schritte zur Lösung

x^{2} + 4 x - 8 y + 4 = 0

Rewrite

x^{2} + 4 x - 8 y + 4 = 0

in the standard form

4 \cdot 2 (y - 0) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 0), p = 2

(x - 1)^{2} = 4 (y - 1)

y = - 0.02 x^{2} + x + 2.6

x^{2} + 3 x + k (x) = 0

x^{2} - 2 y + 4 = 0

x + (y - 1)^{2} = 0