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Beliebt Geometry >

2x^2+2y^2+4x+16y+2=0

Lösung

2 x^{2} + 2 y^{2} + 4 x + 16 y + 2 = 0

Lösung

(a, b) = (- 1, - 4), r = 4

Schritte zur Lösung

2 x^{2} + 2 y^{2} + 4 x + 16 y + 2 = 0

Rewrite

2 x^{2} + 2 y^{2} + 4 x + 16 y + 2 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 4))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 4), r = 4

Graph

Beliebte Beispiele

x^2-4x+y^2+10y=25

x^{2} - 4 x + y^{2} + 10 y = 25

(x-3)^2+(y+2)^2=6

(x - 3)^{2} + (y + 2)^{2} = 6

x^{2} + y^{2} = 2023

x^2+y^2-10x-2y+1=0

x^{2} + y^{2} - 10 x - 2 y + 1 = 0

x^2+y^2-2x+4y+2=0

x^{2} + y^{2} - 2 x + 4 y + 2 = 0