What is x^2+y^2+5x+4y=46 ?

The solution to x^2+y^2+5x+4y=46 is Circle with (a,b)=(-5/2 ,-2),r= 15/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

x^2+y^2+5x+4y=46

x^{2} + y^{2} + 5 x + 4 y = 46

(a, b) = (- \frac{5}{2}, - 2), r = \frac{15}{2}

Solution steps

x^{2} + y^{2} + 5 x + 4 y = 46

Rewrite

x^{2} + y^{2} + 5 x + 4 y = 46

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - (- 2))^{2} = (\frac{15}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, - 2), r = \frac{15}{2}

What is x^2+y^2+5x+4y=46 ?
The solution to x^2+y^2+5x+4y=46 is Circle with (a,b)=(-5/2 ,-2),r= 15/2