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Beliebt Geometry >

2x^2+2y^2-2x+2y-1=0

Lösung

2 x^{2} + 2 y^{2} - 2 x + 2 y - 1 = 0

Lösung

(a, b) = (\frac{1}{2}, - \frac{1}{2}), r = 1

Schritte zur Lösung

2 x^{2} + 2 y^{2} - 2 x + 2 y - 1 = 0

Rewrite

2 x^{2} + 2 y^{2} - 2 x + 2 y - 1 = 0

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - (- \frac{1}{2}))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, - \frac{1}{2}), r = 1

Graph

Beliebte Beispiele

2x^2+2y^2+4x+12y-2=0

2 x^{2} + 2 y^{2} + 4 x + 12 y - 2 = 0

(x-12)^2+(y-4)^2=4

(x - 12)^{2} + (y - 4)^{2} = 4

x^2+y^2+12x-6y+36=0

x^{2} + y^{2} + 12 x - 6 y + 36 = 0

(x-8)^2+(y-1)^2=1

(x - 8)^{2} + (y - 1)^{2} = 1

(x-3)^2+(y-2)^2=36

(x - 3)^{2} + (y - 2)^{2} = 36