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Beliebt Geometry >

y^2+x^2-4x+10y+13=0

Lösung

y^{2} + x^{2} - 4 x + 10 y + 13 = 0

Lösung

(a, b) = (2, - 5), r = 4

Schritte zur Lösung

y^{2} + x^{2} - 4 x + 10 y + 13 = 0

Rewrite

y^{2} + x^{2} - 4 x + 10 y + 13 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 5))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (2, - 5), r = 4

Graph

Beliebte Beispiele

x^2+(y-4)^2= 5/3

x^{2} + (y - 4)^{2} = \frac{5}{3}

x^2+y^2+3x+6y+9=0

x^{2} + y^{2} + 3 x + 6 y + 9 = 0

(x-2)^2+(y-3)^2=10

(x - 2)^{2} + (y - 3)^{2} = 10

9 x^{2} + 9 y^{2} = 64

(x-2)^2+(y-3)^2=49

(x - 2)^{2} + (y - 3)^{2} = 49