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Beliebt Geometry >

4x^2+32x+4y^2=0

Lösung

4 x^{2} + 32 x + 4 y^{2} = 0

Lösung

(a, b) = (- 4, 0), r = 4

Schritte zur Lösung

4 x^{2} + 32 x + 4 y^{2} = 0

Rewrite

4 x^{2} + 32 x + 4 y^{2} = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 4, 0), r = 4

Graph

Beliebte Beispiele

4x^2+4y^2-16x+40y-7=0

4 x^{2} + 4 y^{2} - 16 x + 40 y - 7 = 0

(x-11)^2+(y-12)^2=25

(x - 11)^{2} + (y - 12)^{2} = 25

y^{2} + x^{2} - 4 = 0

x^2+y^2-6x-10y+2=0

x^{2} + y^{2} - 6 x - 10 y + 2 = 0

(x-5)^2+(y-1)^2=4

(x - 5)^{2} + (y - 1)^{2} = 4