2x^2= 2/3 (y-1)

解

2 x^{2} = \frac{2}{3} (y - 1)

(h, k) = (0, 1), p = \frac{1}{12}

解答ステップ

2 x^{2} = \frac{2}{3} (y - 1)

2 x^{2} = \frac{2}{3} (y - 1)

を標準的な形式で書き換える:

4 \cdot \frac{1}{12} (y - 1) = (x - 0)^{2}

ゆえに放物線の特性は:

(h, k) = (0, 1), p = \frac{1}{12}