What is (x-3)^2+(y+4)^2=36 ?

The solution to (x-3)^2+(y+4)^2=36 is Circle with (a,b)=(3,-4),r=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(x-3)^2+(y+4)^2=36

(x - 3)^{2} + (y + 4)^{2} = 36

(a, b) = (3, - 4), r = 6

Solution steps

(x - 3)^{2} + (y + 4)^{2} = 36

Rewrite

(x - 3)^{2} + (y + 4)^{2} = 36

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 4))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (3, - 4), r = 6

What is (x-3)^2+(y+4)^2=36 ?
The solution to (x-3)^2+(y+4)^2=36 is Circle with (a,b)=(3,-4),r=6