What is (x-3)^{(2)}+(y+2)^{(2)}=49 ?

The solution to (x-3)^{(2)}+(y+2)^{(2)}=49 is Circle with (a,b)=(3,-2),r=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(x-3)^{(2)}+(y+2)^{(2)}=49

(x - 3)^{(2)} + (y + 2)^{(2)} = 49

(a, b) = (3, - 2), r = 7

Solution steps

(x - 3)^{2} + (y + 2)^{2} = 49

Rewrite

(x - 3)^{2} + (y + 2)^{2} = 49

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 2))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (3, - 2), r = 7

What is (x-3)^{(2)}+(y+2)^{(2)}=49 ?
The solution to (x-3)^{(2)}+(y+2)^{(2)}=49 is Circle with (a,b)=(3,-2),r=7