What is 4x^2+9y^2+32x-18y+37=0 ?

The solution to 4x^2+9y^2+32x-18y+37=0 is Ellipse with (h,k)=(-4,1),a=3,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2+9y^2+32x-18y+37=0

4 x^{2} + 9 y^{2} + 32 x - 18 y + 37 = 0

(h, k) = (- 4, 1), a = 3, b = 2

Solution steps

4 x^{2} + 9 y^{2} + 32 x - 18 y + 37 = 0

Rewrite

4 x^{2} + 9 y^{2} + 32 x - 18 y + 37 = 0

in the form of the standard ellipse equation

\frac{( x - ( - 4 ) ) ^{2}}{3 ^{2}} + \frac{( y - 1 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 4, 1), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 4, 1), a = 3, b = 2

9 x^{2} + 6 y^{2} + 36 y = 0

\frac{x ^{2}}{a} + \frac{y ^{2}}{b} = 1

3 x^{2} + 2 y^{2} = 4

16 x^{2} + 4 y^{2} = 64

8 x^{2} + 2 y^{2} + 16 x = 0

What is 4x^2+9y^2+32x-18y+37=0 ?
The solution to 4x^2+9y^2+32x-18y+37=0 is Ellipse with (h,k)=(-4,1),a=3,b=2