(x-4)^2+(y+2)^2=9

解答

(x - 4)^{2} + (y + 2)^{2} = 9

(a, b) = (4, - 2), r = 3

求解步骤

(x - 4)^{2} + (y + 2)^{2} = 9

将

(x - 4)^{2} + (y + 2)^{2} = 9

改写为圆标准方程

(x - 4)^{2} + (y - (- 2))^{2} = 3^{2}

因此圆的性质是:

(a, b) = (4, - 2), r = 3

3 x^{2} + 3 y^{2} + 30 x - 12 y - 60 = 0

2 x^{2} + 2 y^{2} - 16 x + 8 y - 10 = 0

x^{2} + x + (p (x)^{2} - 7 p (x)) = 0

4 x^{2} + 4 y^{2} - 32 x + 8 y - 32 = 0

4 x^{2} + 4 y^{2} + 20 x - 32 y = 5