What is (x-5)^2+y^2=9 ?

The solution to (x-5)^2+y^2=9 is Circle with (a,b)=(5,0),r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-5)^2+y^2=9

(x - 5)^{2} + y^{2} = 9

(a, b) = (5, 0), r = 3

Solution steps

(x - 5)^{2} + y^{2} = 9

Rewrite

(x - 5)^{2} + y^{2} = 9

in the form of the standard circle equation

(x - 5)^{2} + (y - 0)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (5, 0), r = 3

(x + 3)^{2} + y^{2} = 4

(x - 3)^{2} + (y + 1)^{2} = 25

3 x^{2} + 3 y^{2} - 18 y + 3 = 0

(x - 2)^{2} + (y + 5)^{2} = 36

x^{2} + y^{2} - 8 x + 12 y + 16 = 0

What is (x-5)^2+y^2=9 ?
The solution to (x-5)^2+y^2=9 is Circle with (a,b)=(5,0),r=3