What is x^2+y^2+6x+5y=(-45)/4 ?

The solution to x^2+y^2+6x+5y=(-45)/4 is Circle with (a,b)=(-3,-5/2),r=2

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x^2+y^2+6x+5y=(-45)/4

x^{2} + y^{2} + 6 x + 5 y = \frac{- 45}{4}

(a, b) = (- 3, - \frac{5}{2}), r = 2

Solution steps

x^{2} + y^{2} + 6 x + 5 y = \frac{- 45}{4}

Rewrite

x^{2} + y^{2} + 6 x + 5 y = \frac{- 45}{4}

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- \frac{5}{2}))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 3, - \frac{5}{2}), r = 2

x^{2} + y^{2} - 4 x - 21 = 0

(x - 4)^{2} + (y + 3)^{2} = 4

(x - 2)^{2} + (y + 1)^{2} = 2

x^{2} + y^{2} - 6 y + 4 = 0

x^{2} + y^{2} - 4 x + 12 y + 4 = 0

What is x^2+y^2+6x+5y=(-45)/4 ?
The solution to x^2+y^2+6x+5y=(-45)/4 is Circle with (a,b)=(-3,-5/2),r=2