What is y^{(2)}-10y-5x+15=0 ?

The solution to y^{(2)}-10y-5x+15=0 is Parabola with (h,k)=(-2,5),p= 5/4

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y^{(2)}-10y-5x+15=0

y^{(2)} - 10 y - 5 x + 15 = 0

(h, k) = (- 2, 5), p = \frac{5}{4}

Solution steps

y^{2} - 10 y - 5 x + 15 = 0

Rewrite

y^{2} - 10 y - 5 x + 15 = 0

in the standard form

4 \cdot \frac{5}{4} (x - (- 2)) = (y - 5)^{2}

Therefore parabola properties are:

(h, k) = (- 2, 5), p = \frac{5}{4}

x^{2} + y = - 1

5 x^{2} + 30 x + 24 y = 51

(x - 2)^{2} = 4 (y + 5)

x = y^{2} + 2

y^{2} = 9 x

What is y^{(2)}-10y-5x+15=0 ?
The solution to y^{(2)}-10y-5x+15=0 is Parabola with (h,k)=(-2,5),p= 5/4