What is (x-7)^2+(y-7)^2= 4/9 ?

The solution to (x-7)^2+(y-7)^2= 4/9 is Circle with (a,b)=(7,7),r= 2/3

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(x-7)^2+(y-7)^2= 4/9

(x - 7)^{2} + (y - 7)^{2} = \frac{4}{9}

(a, b) = (7, 7), r = \frac{2}{3}

Solution steps

(x - 7)^{2} + (y - 7)^{2} = \frac{4}{9}

Rewrite

(x - 7)^{2} + (y - 7)^{2} = \frac{4}{9}

in the form of the standard circle equation

(x - 7)^{2} + (y - 7)^{2} = (\frac{2}{3})^{2}

Therefore the circle properties are:

(a, b) = (7, 7), r = \frac{2}{3}

x^{2} + y^{2} - 10 x + 6 y + 18 = 0

(x + 3)^{2} + (y - 4)^{2} = 49

x^{2} + y^{2} - 6 x + 2 y + 1 = 0

x^{2} + y^{2} - 4 x + 10 y + 23 = 0

4 x^{2} + 4 y^{2} + 8 x - 16 y - 29 = 0

What is (x-7)^2+(y-7)^2= 4/9 ?
The solution to (x-7)^2+(y-7)^2= 4/9 is Circle with (a,b)=(7,7),r= 2/3