What is x=-1/2 (y-4)^2+1/2 ?

The solution to x=-1/2 (y-4)^2+1/2 is Parabola with (h,k)=(1/2 ,4),p=-1/2

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x=-1/2 (y-4)^2+1/2

x = - \frac{1}{2} (y - 4)^{2} + \frac{1}{2}

(h, k) = (\frac{1}{2}, 4), p = - \frac{1}{2}

Solution steps

x = - \frac{1}{2} (y - 4)^{2} + \frac{1}{2}

Rewrite

x = - \frac{1}{2} (y - 4)^{2} + \frac{1}{2}

in the standard form:

4 (- \frac{1}{2}) (x - \frac{1}{2}) = (y - 4)^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, 4), p = - \frac{1}{2}

x^{2} - y = 9

3 x^{2} - 9 x - 5 y - 2 = 0

\frac{3 y ^{2} - 30 y + 2 x + 101}{2} = 0

y^{2} - 15 y = y^{2} - 3 x

(y - 7)^{2} = 24 (x + 1)

What is x=-1/2 (y-4)^2+1/2 ?
The solution to x=-1/2 (y-4)^2+1/2 is Parabola with (h,k)=(1/2 ,4),p=-1/2