What is x^2+y^2+10x-14y=26 ?

The solution to x^2+y^2+10x-14y=26 is Circle with (a,b)=(-5,7),r=10

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x^2+y^2+10x-14y=26

x^{2} + y^{2} + 10 x - 14 y = 26

(a, b) = (- 5, 7), r = 10

Solution steps

x^{2} + y^{2} + 10 x - 14 y = 26

Rewrite

x^{2} + y^{2} + 10 x - 14 y = 26

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 7)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 5, 7), r = 10

x^{2} - 2 x + y^{2} - 6 y - 27 = 0

x^{2} + y^{2} - 225 = 0

x^{2} + y^{2} < 16

x^{2} - 6 x + y^{2} + 4 y + 4 = 0

x^{2} + y^{2} - 4 x + 2 y - 11 = 0

What is x^2+y^2+10x-14y=26 ?
The solution to x^2+y^2+10x-14y=26 is Circle with (a,b)=(-5,7),r=10