What is (x-1/2)^2+(y-1/2)^2= 9/4 ?

The solution to (x-1/2)^2+(y-1/2)^2= 9/4 is Circle with (a,b)=(1/2 , 1/2),r= 3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-1/2)^2+(y-1/2)^2= 9/4

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{9}{4}

(a, b) = (\frac{1}{2}, \frac{1}{2}), r = \frac{3}{2}

Solution steps

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{9}{4}

Rewrite

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{9}{4}

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, \frac{1}{2}), r = \frac{3}{2}

y^{2} + x^{2} = 100

x^{2} + y^{2} \leq 2 x

x^{2} + y^{2} - 8 x + 2 y + 1 = 0

x^{2} + y^{2} + 16 x - 10 y + 81 = 0

(x + 1)^{2} + (y - 1)^{2} = 1.25

What is (x-1/2)^2+(y-1/2)^2= 9/4 ?
The solution to (x-1/2)^2+(y-1/2)^2= 9/4 is Circle with (a,b)=(1/2 , 1/2),r= 3/2