What is x^2-6x+y^2-8y=0 ?

The solution to x^2-6x+y^2-8y=0 is Circle with (a,b)=(3,4),r=5

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x^2-6x+y^2-8y=0

x^{2} - 6 x + y^{2} - 8 y = 0

(a, b) = (3, 4), r = 5

Solution steps

x^{2} - 6 x + y^{2} - 8 y = 0

Rewrite

x^{2} - 6 x + y^{2} - 8 y = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 4)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (3, 4), r = 5

(x - 1)^{2} + (y + 5)^{2} = 16

(x + 2)^{2} + (y - 3)^{2} = 4

(x - 6)^{2} + (y + 3)^{2} = 16

4 x^{2} + 4 y^{2} + 8 x - y = 0

9 x^{2} + 9 y^{2} = 1

What is x^2-6x+y^2-8y=0 ?
The solution to x^2-6x+y^2-8y=0 is Circle with (a,b)=(3,4),r=5