What is (x-3/4)^2+(y+5/4)^2=2 ?

The solution to (x-3/4)^2+(y+5/4)^2=2 is Circle with (a,b)=(3/4 ,-5/4),r=sqrt(2)

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(x-3/4)^2+(y+5/4)^2=2

(x - \frac{3}{4})^{2} + (y + \frac{5}{4})^{2} = 2

(a, b) = (\frac{3}{4}, - \frac{5}{4}), r = 2

Solution steps

(x - \frac{3}{4})^{2} + (y + \frac{5}{4})^{2} = 2

Rewrite

(x - \frac{3}{4})^{2} + (y + \frac{5}{4})^{2} = 2

in the form of the standard circle equation

(x - \frac{3}{4})^{2} + (y - (- \frac{5}{4}))^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{4}, - \frac{5}{4}), r = 2

x^{2} + y^{2} = 8 x

x^{2} + y^{2} + 8 y = 2 x + 20

(x - 1)^{2} + (y - 1)^{2} = 1

x^{2} + y^{2} + 7 x - 8 y = 3

x^{2} + y^{2} + 6 x - 8 y = 0

What is (x-3/4)^2+(y+5/4)^2=2 ?
The solution to (x-3/4)^2+(y+5/4)^2=2 is Circle with (a,b)=(3/4 ,-5/4),r=sqrt(2)