What is x^2+y^2-8x+12y=-43 ?

The solution to x^2+y^2-8x+12y=-43 is Circle with (a,b)=(4,-6),r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-8x+12y=-43

x^{2} + y^{2} - 8 x + 12 y = - 43

(a, b) = (4, - 6), r = 3

Solution steps

x^{2} + y^{2} - 8 x + 12 y = - 43

Rewrite

x^{2} + y^{2} - 8 x + 12 y = - 43

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 6))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (4, - 6), r = 3

x^{2} + z^{2} = 9

(x + 5)^{2} + (y - 1)^{2} = 9

x^{2} + y^{2} - 2 x + 12 y - 12 = 0

4 x^{2} + 4 y^{2} - 16 x + 4 y - 47 = 0

y^{2} = - x^{2} + 4

What is x^2+y^2-8x+12y=-43 ?
The solution to x^2+y^2-8x+12y=-43 is Circle with (a,b)=(4,-6),r=3