What is 9x^2+9y^2+12x+36y-104=0 ?

The solution to 9x^2+9y^2+12x+36y-104=0 is Circle with (a,b)=(-2/3 ,-2),r=4

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9x^2+9y^2+12x+36y-104=0

9 x^{2} + 9 y^{2} + 12 x + 36 y - 104 = 0

(a, b) = (- \frac{2}{3}, - 2), r = 4

Solution steps

9 x^{2} + 9 y^{2} + 12 x + 36 y - 104 = 0

Rewrite

9 x^{2} + 9 y^{2} + 12 x + 36 y - 104 = 0

in the form of the standard circle equation

(x - (- \frac{2}{3}))^{2} + (y - (- 2))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- \frac{2}{3}, - 2), r = 4

x^{2} + y^{2} + 4 x = 0

x^{2} + y^{2} + 6 x - 10 y + 18 = 0

4 - x^{2} - y^{2} > 0

x^{2} + y^{2} - 10 x + 9 y + 1 = 0

16 - x^{2} - y^{2} \geq 0

What is 9x^2+9y^2+12x+36y-104=0 ?
The solution to 9x^2+9y^2+12x+36y-104=0 is Circle with (a,b)=(-2/3 ,-2),r=4