What is x^2+(y-3)^2=14 ?

The solution to x^2+(y-3)^2=14 is Circle with (a,b)=(0,3),r=sqrt(14)

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x^2+(y-3)^2=14

x^{2} + (y - 3)^{2} = 14

(a, b) = (0, 3), r = 14

Solution steps

x^{2} + (y - 3)^{2} = 14

Rewrite

x^{2} + (y - 3)^{2} = 14

in the form of the standard circle equation

(x - 0)^{2} + (y - 3)^{2} = (14)^{2}

Therefore the circle properties are:

(a, b) = (0, 3), r = 14

(x + 5)^{2} + (y - 3)^{2} = 9

(x + 4)^{2} + (y + 3)^{2} = 25

\frac{9}{2} x^{2} + \frac{9}{2} y^{2} = 1

(x - 3)^{2} + (y + 2)^{2} = 4

x^{2} + y^{2} > 4

What is x^2+(y-3)^2=14 ?
The solution to x^2+(y-3)^2=14 is Circle with (a,b)=(0,3),r=sqrt(14)