What is x^2+(y-3)^2=4 ?

The solution to x^2+(y-3)^2=4 is Circle with (a,b)=(0,3),r=2

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x^2+(y-3)^2=4

x^{2} + (y - 3)^{2} = 4

(a, b) = (0, 3), r = 2

Solution steps

x^{2} + (y - 3)^{2} = 4

Rewrite

x^{2} + (y - 3)^{2} = 4

in the form of the standard circle equation

(x - 0)^{2} + (y - 3)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 3), r = 2

x^{2} + y^{2} + 4 x - 6 y + 9 = 0

(x + 3)^{2} + (y - 2)^{2} = 4

(x + 1)^{2} + y^{2} = 4

(x - 2)^{2} + (y + 1)^{2} = 25

x^{2} + y^{2} + 2 x + 4 y - 4 = 0

What is x^2+(y-3)^2=4 ?
The solution to x^2+(y-3)^2=4 is Circle with (a,b)=(0,3),r=2