What is x^2+y^2+14x-12y+4=0 ?

The solution to x^2+y^2+14x-12y+4=0 is Circle with (a,b)=(-7,6),r=9

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x^2+y^2+14x-12y+4=0

x^{2} + y^{2} + 14 x - 12 y + 4 = 0

(a, b) = (- 7, 6), r = 9

Solution steps

x^{2} + y^{2} + 14 x - 12 y + 4 = 0

Rewrite

x^{2} + y^{2} + 14 x - 12 y + 4 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 6)^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (- 7, 6), r = 9

3 x^{2} + 3 y^{2} - 6 y - 1 = 0

x^{2} + y^{2} + 6 x - 16 = 0

4 - x^{2} - y^{2} \geq 0

x^{2} + y^{2} + 12 x - 4 y + 4 = 0

x^{2} + y^{2} - 2 x - 2 y - 2 = 0

What is x^2+y^2+14x-12y+4=0 ?
The solution to x^2+y^2+14x-12y+4=0 is Circle with (a,b)=(-7,6),r=9