What is 9x^2+9y^2+72x+6y+1=0 ?

The solution to 9x^2+9y^2+72x+6y+1=0 is Circle with (a,b)=(-4,-1/3),r=4

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9x^2+9y^2+72x+6y+1=0

9 x^{2} + 9 y^{2} + 72 x + 6 y + 1 = 0

(a, b) = (- 4, - \frac{1}{3}), r = 4

Solution steps

9 x^{2} + 9 y^{2} + 72 x + 6 y + 1 = 0

Rewrite

9 x^{2} + 9 y^{2} + 72 x + 6 y + 1 = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- \frac{1}{3}))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 4, - \frac{1}{3}), r = 4

x^{2} + (y - 3)^{2} = 16

(x - 2)^{2} + (y + 1)^{2} = 16

3 x^{2} + 3 y^{2} = 27

(x - 0)^{2} + (y - 0)^{2} = 49

(x - 3)^{2} + (y + 2)^{2} = 16

What is 9x^2+9y^2+72x+6y+1=0 ?
The solution to 9x^2+9y^2+72x+6y+1=0 is Circle with (a,b)=(-4,-1/3),r=4