What is (x^2)/(49)+(y^2)/(49)=1 ?

The solution to (x^2)/(49)+(y^2)/(49)=1 is Circle with (a,b)=(0,0),r=7

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(x^2)/(49)+(y^2)/(49)=1

\frac{x ^{2}}{49} + \frac{y ^{2}}{49} = 1

(a, b) = (0, 0), r = 7

Solution steps

\frac{x ^{2}}{49} + \frac{y ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{49} + \frac{y ^{2}}{49} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 7

x^{2} + y^{2} + 4 x - 6 y - 10 = 0

x^{2} + (y + 1)^{2} = 4

y^{2} + z^{2} = 4

y^{2} + x^{2} = 4

x^{2} + y^{2} - 6 y + 5 = 0

What is (x^2)/(49)+(y^2)/(49)=1 ?
The solution to (x^2)/(49)+(y^2)/(49)=1 is Circle with (a,b)=(0,0),r=7