What is y^2+4x-20-2y=-x^2 ?

The solution to y^2+4x-20-2y=-x^2 is Circle with (a,b)=(-2,1),r=5

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y^2+4x-20-2y=-x^2

y^{2} + 4 x - 20 - 2 y = - x^{2}

(a, b) = (- 2, 1), r = 5

Solution steps

y^{2} + 4 x - 20 - 2 y = - x^{2}

Rewrite

y^{2} + 4 x - 20 - 2 y = - x^{2}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 1)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 2, 1), r = 5

(x - 3)^{2} + (y - 4)^{2} = 4

x^{2} + y^{2} + 4 x - 10 y + 13 = 0

x^{2} + y^{2} - 2 x - 6 y - 6 = 0

x^{2} + (y - 5)^{2} = 25

x^{2} + y^{2} - 8 x = 0

What is y^2+4x-20-2y=-x^2 ?
The solution to y^2+4x-20-2y=-x^2 is Circle with (a,b)=(-2,1),r=5