What is 3x^2-5x+3y^2+5y-8=0 ?

The solution to 3x^2-5x+3y^2+5y-8=0 is Circle with (a,b)=(5/6 ,-5/6),r=(sqrt(73))/(3sqrt(2))

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3x^2-5x+3y^2+5y-8=0

3 x^{2} - 5 x + 3 y^{2} + 5 y - 8 = 0

(a, b) = (\frac{5}{6}, - \frac{5}{6}), r = \frac{73}{3 2}

Solution steps

3 x^{2} - 5 x + 3 y^{2} + 5 y - 8 = 0

Rewrite

3 x^{2} - 5 x + 3 y^{2} + 5 y - 8 = 0

in the form of the standard circle equation

(x - \frac{5}{6})^{2} + (y - (- \frac{5}{6}))^{2} = (\frac{73}{3 2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{6}, - \frac{5}{6}), r = \frac{73}{3 2}

(x + 4)^{2} + (y - 3)^{2} = 16

x^{2} + y^{2} + 6 x + 8 x = - 16

x^{2} + y^{2} - 10 x - 6 y + 25 = 0

x^{2} + y^{2} > 1

3 x^{2} + 3 y^{2} - 2 x + y - 6 = 0

What is 3x^2-5x+3y^2+5y-8=0 ?
The solution to 3x^2-5x+3y^2+5y-8=0 is Circle with (a,b)=(5/6 ,-5/6),r=(sqrt(73))/(3sqrt(2))