What is x^2+y^2+2x=3y ?

The solution to x^2+y^2+2x=3y is Circle with (a,b)=(-1, 3/2),r=(sqrt(13))/2

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x^2+y^2+2x=3y

x^{2} + y^{2} + 2 x = 3 y

(a, b) = (- 1, \frac{3}{2}), r = \frac{13}{2}

Solution steps

x^{2} + y^{2} + 2 x = 3 y

Rewrite

x^{2} + y^{2} + 2 x = 3 y

in the form of the standard circle equation

(x - (- 1))^{2} + (y - \frac{3}{2})^{2} = (\frac{13}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 1, \frac{3}{2}), r = \frac{13}{2}

(x - 3)^{2} + (y + 1)^{2} = 4

(x - 2)^{2} + y^{2} = 4

x^{2} + y^{2} - 6 x + 10 y + 9 = 0

16 x^{2} + 16 y^{2} = 320

(x - 2)^{2} + (y + 1)^{2} = 9

What is x^2+y^2+2x=3y ?
The solution to x^2+y^2+2x=3y is Circle with (a,b)=(-1, 3/2),r=(sqrt(13))/2