What is the area (x+3)^2+(3-x) ?

The area (x+3)^2+(3-x) is Unbounded

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area (x+3)^2+(3-x)

area

(x + 3)^{2} + (3 - x)

Unbounded

Solution steps

y = (x + 3)^{2} + 3 - x

Rewrite

y = (x + 3)^{2} + 3 - x

in the standard form

4 \cdot \frac{1}{4} (y - \frac{23}{4}) = (x - (- \frac{5}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{2}, \frac{23}{4}), p = \frac{1}{4}

Parabola's area is always unbounded

Unbounded

- 0.29 x^{2} + 2.5 x

y = 49 - x^{2}

2 x - x^{2} - 1

\frac{x ^{2}}{8 [ 3 , 7 ]}

f (x) = - x^{2} + 3 x + 5