What is the area (6a+4y)^2 ?

The area (6a+4y)^2 is Unbounded

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area (6a+4y)^2

area

(6 a + 4 y)^{2}

Unbounded

Solution steps

x = (6 a + 4 y)^{2}

Rewrite

x = (6 a + 4 y)^{2}

in the standard form:

4 \cdot \frac{1}{64} (x - 0) = (y - (- \frac{3 a}{2}))^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{3 a}{2}), p = \frac{1}{64}

Parabola's area is always unbounded

Unbounded

f (x) = 8 + 2 x^{2}

y = x^{2} - 3

f (x) = (2 x + 1)^{2}

f (x) = x^{2} - x - 6

f (x) = x^{2} - x - 2