What is the area 2+y^2-6x+2y+1=0 ?

The area 2+y^2-6x+2y+1=0 is Unbounded

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area 2+y^2-6x+2y+1=0

area

2 + y^{2} - 6 x + 2 y + 1 = 0

Unbounded

Solution steps

2 + y^{2} - 6 x + 2 y + 1 = 0

Rewrite

2 + y^{2} - 6 x + 2 y + 1 = 0

in the standard form

4 \cdot \frac{3}{2} (x - \frac{1}{3}) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{3}, - 1), p = \frac{3}{2}

Parabola's area is always unbounded

Unbounded

f (x) = x^{2} - 6 x

y^{2} = - x

x^{2} - 6 x + 6

y = - x^{2} + 12 x - 32

[(2 - x^{2})]