What is the area y^2=x[1,16] ?

The area y^2=x[1,16] is Unbounded

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area y^2=x[1,16]

area

y^{2} = x [1, 16]

Unbounded

Solution steps

y^{2} = x [1, 16]

Rewrite

y^{2} = x [1, 16]

in the standard form:

4 \cdot \frac{1}{4 ( \frac{1}{[ 1 , 16 ]} )} (x - (- \frac{0}{1 , 16})) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{0}{1 , 16}, 0), p = \frac{1}{4 ( \frac{1}{[ 1 , 16 ]} )}

Parabola's area is always unbounded

Unbounded

x^{2} + 3

x^{2} + 5

f (x) = 81 - x^{2}

Y = X^{2}

Y (x) = x^{2} - 2 x + 2