What is the axis y=6x^2-4 ?

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axis y=6x^2-4

axis

y = 6 x^{2} - 4

x = 0

Solution steps

y = 6 x^{2} - 4

Rewrite

y = 6 x^{2} - 4

in the standard form:

4 \cdot \frac{1}{24} (y - (- 4)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 4), p = \frac{1}{24}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 3 x^{2} + 15 x

y = - 2 x^{2} + 11

x^{2} - 4 x - 8 y + 12 = 0

y = x^{2} + 10 x

x = (- 20 y + 13)^{2}