What is the axis f(x)=-3x^2+5x-2 ?

The axis f(x)=-3x^2+5x-2 is x= 5/6

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axis f(x)=-3x^2+5x-2

axis

f (x) = - 3 x^{2} + 5 x - 2

x = \frac{5}{6}

Solution steps

y = - 3 x^{2} + 5 x - 2

Rewrite

y = - 3 x^{2} + 5 x - 2

in the standard form

4 (- \frac{1}{12}) (y - \frac{1}{12}) = (x - \frac{5}{6})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{6}, \frac{1}{12}), p = - \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{5}{6}

- x^{2} + 10 x - 24

y = \frac{x ^{2} - 16 x + 70}{2}

x = (2 y + 5) (y + 6)

y = x^{2} + 12 x + 43

y = (0.5 - x)^{2}