What is the axis y=2x^2-12x+18 ?

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axis y=2x^2-12x+18

axis

y = 2 x^{2} - 12 x + 18

x = 3

Solution steps

y = 2 x^{2} - 12 x + 18

Rewrite

y = 2 x^{2} - 12 x + 18

in the standard form

4 \cdot \frac{1}{8} (y - 0) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 0), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 3

x^{2} - 8 y = 0

y = - 9 x^{2} + 700 x - 6005

(y - 2)^{2} = 40 (x - 2)

y = \frac{1}{2} x^{2} + 2

y = 2 x^{2} - 12 x + 22