What is the axis y=-4(x+10)^2+6 ?

The axis y=-4(x+10)^2+6 is x=-10

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axis y=-4(x+10)^2+6

axis

y = - 4 (x + 10)^{2} + 6

x = - 10

Solution steps

y = - 4 (x + 10)^{2} + 6

Rewrite

y = - 4 (x + 10)^{2} + 6

in the standard form:

4 (- \frac{1}{16}) (y - 6) = (x - (- 10))^{2}

Therefore parabola properties are:

(h, k) = (- 10, 6), p = - \frac{1}{16}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 10

(x + 1)^{2} = - 3 (y - 6)

y = 10 x^{2} + 1 - 6 x

y = - 8 x^{2} + 4 x

- 3 y = x^{2} - 8 x + 37

y = - 2 x^{2} + 12 x - 10